All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
As easy as 123 (Posted on 2013-10-25) Difficulty: 3 of 5
In the multiplication of two 3-digit numbers, all digits Except 1,2, and 3 were either erased or were not initially a part of the process.

Fill in the missing digits if 3EE*EEE=2E11E1 and the partial products (in some order) were: 2EE2, 2EE3, and 3321.

  Submitted by Ady TZIDON    
No Rating
Solution: (Hide)
3321 is factorized 9*369, ,the only way to get 3 digit multiplicand i.e. 369
the rest easily follows, leading to 369*789=291,141/

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Solution/spoilerxdog2013-10-25 10:51:22
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (12)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information