All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
LCM equation (Posted on 2013-11-19) Difficulty: 2 of 5
The least common multiple (LCM) of 2 numbers is the smallest number that they both divide evenly into.
e.g.:
LCM(8,10)=40
LCM(17,11)=187

For any integer n, show that LCM(9n + 8, 6n + 5) = 54n^2 + 93n + 40.

No Solution Yet Submitted by Ady TZIDON    
Rating: 4.3333 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Proof | Comment 5 of 6 |
GCD(9n+8, 6n+5)=GCD(6n+5, 3n+3)=GCD(3n+3, 3n+2)=GCD(3n+2, 1)=1
Therefore, LCM(9n+8, 6n+5)=(9n+8)(6n+5)=54n^2+93n+40.


  Posted by Math Man on 2013-11-26 22:57:04
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (9)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information