(In reply to
possible solution by broll)
Nice solution.
I got close but then I cheated.
I didn't try simplifying the 'heroic' equation.
Instead I subbed a and b into III and solved for y in terms of x using the quadratic equation. (Gives two solutions with ±)
Then I subbed a,b, and y in for x and graphed IV on my calculator.
The + gives {x,y,b,a} = {2,3,25,2}
The  gives {x,y,b,a} = {3,2,2,25}
Is there a way to solve this without finding the values of all the variables?

Posted by Jer
on 20131007 09:59:24 