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On the same line (Posted on 2013-12-22) Difficulty: 3 of 5
Let ABC be a triangle.
Let the point P lie in the plane of ABC.
Let X, Y, Z be the feet of the perpendiculars from P to the lines BC, AC, AB respectively.

PROVE:  : The points X, Y , Z are collinear if and only if P lies on the circumcircle of ABC.

See The Solution Submitted by Ady TZIDON    
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re: Solution | Comment 2 of 3 |
(In reply to Solution by Harry)

What about special cases like P coincides with A ( how do you 

define angle PAZ? ) or line XYZ coincides with line BC?

  Posted by Bractals on 2013-12-23 21:09:21
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