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A missing proverb (Posted on 2014-01-09) Difficulty: 3 of 5
Solve the alphametics:

words * war = actions

and complete the following phrase:

(-)23u870 (-) 23470 (-) 2340e (-) (-)23u870 (-) 02347.


each (-) .... Represents a short missing word.

See The Solution Submitted by Ady TZIDON    
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Solution computer solution | Comment 1 of 2

DECLARE SUB permute (a$)
CLS
a$ = "1234567890": h$ = a$
DO
    IF INSTR(a$, "0") > 2 THEN
        w = VAL(MID$(a$, 1, 1))
        a = VAL(MID$(a$, 2, 1))
        o = VAL(MID$(a$, 3, 1))
        r = VAL(MID$(a$, 4, 1))
        d = VAL(MID$(a$, 5, 1))
        s = VAL(MID$(a$, 6, 1))
        c = VAL(MID$(a$, 7, 1))
        t = VAL(MID$(a$, 8, 1))
        i = VAL(MID$(a$, 9, 1))
        n = VAL(MID$(a$, 10, 1))
        words = 10000 * w + 1000 * o + 100 * r + 10 * d + s
        war = 100 * w + 10 * a + r
        actions = 1000000 * a + 100000 * c + 10000 * t + 1000 * i + 100 * o + 10 * n + s
        IF words * war = actions THEN
            PRINT w; a; o; r; d; s; c; t; i; n
            PRINT "w; a; o; r; d; s; c; t; i; n"
        END IF
    END IF
    permute a$
LOOP UNTIL a$ = h$

SUB permute (a$)
DEFINT A-Z
x$ = ""
FOR i = LEN(a$) TO 1 STEP -1
    l$ = x$
    x$ = MID$(a$, i, 1)
    IF x$ < l$ THEN EXIT FOR
NEXT

IF i = 0 THEN
    FOR j = 1 TO LEN(a$) \ 2
        x$ = MID$(a$, j, 1)
        MID$(a$, j, 1) = MID$(a$, LEN(a$) - j + 1, 1)
        MID$(a$, LEN(a$) - j + 1, 1) = x$
    NEXT
ELSE
    FOR j = LEN(a$) TO i + 1 STEP -1
        IF MID$(a$, j, 1) > x$ THEN EXIT FOR
    NEXT
    MID$(a$, i, 1) = MID$(a$, j, 1)
    MID$(a$, j, 1) = x$
    FOR j = 1 TO (LEN(a$) - i) \ 2
        x$ = MID$(a$, i + j, 1)
        MID$(a$, i + j, 1) = MID$(a$, LEN(a$) - j + 1, 1)
        MID$(a$, LEN(a$) - j + 1, 1) = x$
    NEXT
END IF
END SUB

finds the correspondence:

 2  5  3  4  7  0  9  6  1  8
w; a; o; r; d; s; c; t; i; n

Then, filling in with short missing words, we get:

(the) wounds (from) words (are) worse (than) (the) wounds (from) sword.


  Posted by Charlie on 2014-01-09 18:47:47
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