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Factorial-Square Sum (Posted on 2014-03-23) Difficulty: 3 of 5
Determine all possible triplets (X,Y,Z) of positive integers that satisfy:

                          X!*Y! = X! + Y! + Z2

Prove that there are no others.

No Solution Yet Submitted by K Sengupta    
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Comments: ( Back to comment list | You must be logged in to post comments.)
Hints/Tips just by looking at it | Comment 1 of 7
(2,2,0)
(3,2,2)
(2,3,2)

  Posted by Ady TZIDON on 2014-03-23 09:34:14
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