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Factorial-Square Sum (Posted on 2014-03-23) Difficulty: 3 of 5
Determine all possible triplets (X,Y,Z) of positive integers that satisfy:

                          X!*Y! = X! + Y! + Z2

Prove that there are no others.

No Solution Yet Submitted by K Sengupta    
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erroneous addition erased by Ady

Edited on March 25, 2014, 9:20 am
  Posted by Ady TZIDON on 2014-03-23 09:50:51

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