A sheet of paper is in the form of a triangle ABC in which AB=3, BC=4 and CA = 5. D is a point in AB such that AD = 1
The paper is folded so that C coincides with D and the resultant crease meets BC at the point X.
Find the length of BX.
The fold forms right triangle BXD with legs BX and 2 and hypotenuse (4BX). A little Pythagoras gives BX=4/3.
I don't understand where perpendicular bisectors come in, but since the solution I propose seems a little light for a 3, maybe that's my problem.

Posted by xdog
on 20140401 21:05:44 