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Similar Triangles (Posted on 2013-11-15) Difficulty: 3 of 5

Let ABCD be a simple quadrilateral.

Construct with straightedge and compass a point P
such that ΔPAB ~ ΔPCD and both triangles have the
same orientation.

See The Solution Submitted by Bractals    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Solution | Comment 2 of 10 |
(In reply to Solution by Harry)

What about the simple case when AB and CD are parallel?
  Posted by Bractals on 2013-11-24 14:59:58

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