(In reply to
Argand  grand! by Harry)
No. the following constructon is standard.
Construct ray AP' such that /BAP' = /FAC.
Construct ray BP" such that /ABP" = /AFC.
P is the intersection of AP' and BP".
Bye the way, how would you solve the problem if the triangles should have opposite orientation.

Posted by Bractals
on 20131128 22:36:03 