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Four special squares (Posted on 2014-01-30) Difficulty: 3 of 5
There are only four squares that are equal to the sum of three consecutive cubes.

Zero is one of them.

Find the other three.

No Solution Yet Submitted by Ady TZIDON    
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re(2): solutions | Comment 4 of 5 |
(In reply to re: solutions by Charlie)

That's what I meant

(x-1)^3 + x^3 + (x+1)^3 = y^2
3*x^3 + 6*x = y^2

I found as you did four solutions

How can we prove analytically that no other solutions exist?

  Posted by Benny on 2014-01-30 19:01:02
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