All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes
Fold Ratio (Posted on 2014-04-05) Difficulty: 3 of 5
  1. A square piece of paper ABCD is folded such that A coincides with the midpoint M of the side BC.
  2. The resulting crease intersects AB in X and CD in Y.
Determine the ratio |AX|:|DY|

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution I can almost do it in my head. Comment 2 of 2 |
This ratio will be true for any square so for simplicity let
A = (0,0) B=(0,1) C=(1,1) D=(1,0)
M=(.5,1)
Midpoint AM=(.25,.5)
Slope AM=2
The crease is the perpendicular bisector of AM
y-.5=-.5(x-.25)
y=-.5x+6.25
X=(0,.625)
AX=.625
If x=1, y=.125
Y=(1,.125)
DY=.125
AX/DY=.625/.125=5


  Posted by Jer on 2014-04-07 00:27:59
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (9)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information