Let n be an integer, and let (Ln) signify the nth Lucas Number.
((Ln)2+(Ln+1)2)2 - 5((L2n+2)*(L2n)-1) = 0
(In reply to re(3): Long solution.
Wouldn't you need to prove this? (It is far from obvious to me.) That wouldn't make the proof shorter.
Posted by Jer
on 2013-12-17 11:06:49