Let n be a positive integer. By removing the last three digits of n, one gets the cube
root of n. Find a possible value of n.

If the 5 digit number n=r^3 begins by ab and the truncated part is cde, ab is **( more than 1000) times less than n.**

It is also** n^2 times less than n.**

Take **( more than 1000)=1024 = 32 squared**

and therefore** ab=32 and abcde=32*1024=30768**

**Clearly ,** there are no other solutions.