Let n be a positive integer. By removing the last three digits of n, one gets the cube
root of n. Find a possible value of n.
If the 5 digit number n=r^3 begins by ab and the truncated part is cde, ab is ( more than 1000) times less than n.
It is also n^2 times less than n.
Take ( more than 1000)=1024 = 32 squared
and therefore ab=32 and abcde=32*1024=30768
Clearly , there are no other solutions.