Determine all possible values of a 5digit positive integer N, such that:
 The first two digits of N, read as a two digit number, are three times the third digit, and:
 The last two digits of N (read as a two digit number) are twice the third digit, and:
 The sum of all the digits of N is 27.
Prove that there are no others.
Exhaust the centerdigit possibilities:
00000 isn't a 5digit number and doesn't add to 27
03102 has leading zero and adds to 6
06204 similar problems
09306 also
12408 adds to 15
15510 adds to 12
18612 adds to 18
21714 adds to 15
24816 adds to 21
27918 adds to 27 solution

Posted by Charlie
on 20140422 13:28:47 