Determine all possible values of a 5digit positive integer N, such that:
 The first two digits of N, read as a two digit number, are three times the third digit, and:
 The last two digits of N (read as a two digit number) are twice the third digit, and:
 The sum of all the digits of N is 27.
Prove that there are no others.
(In reply to
Proof by Charlie)
The middle digit must be a multiple of 3 for the sum of digits to be a multiple of 9.
You only need to check 3, 6 and 9

Posted by Jer
on 20140424 01:32:35 