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 Cinq Carve (Posted on 2014-04-25)
Consider a rectangular piece of paper ABCD with AB ≠ AD

Show how you can fold this piece of paper into five pieces of equal area.

*** Using any given instrument like straightedge, compass, protractor, ruler etc. is NOT permissible.

 No Solution Yet Submitted by K Sengupta Rating: 4.0000 (1 votes)

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 New, simpler solution. | Comment 6 of 7 |
I was trying to draw my previous solution and I came across an idea that renders moot what Steve and I were discussing.

All you need is 5 equal spaces on part of one side and a diagonal line through them.

Fold B and C less than a fifth of the way to A and D (creates a narrow rectangle.)
Repeat 4 more times and unfold.
Call the point where the last of these creases meet edge CD by I
Make crease IB.
This new crease crosses 4 of the 5 creases that are parallel to BC.  They do so at points 1/5, 2/5, 3/5 and 4/5 of the way from edge AB to CD.
So we are basically done.
Just fold C and D towards B and A such that the crease passes through each of these 4 points and you have 5 equal rectangles.

(This solution works for any aspect ratio rectangle.)

 Posted by Jer on 2014-04-27 01:21:40

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