From a full 52card deck of playing cards some cards were removed.
Now we shuffle and draw 2 cards and find them both red.
Given:
1. The probability of both cards being red was 50%.
2. There was an equal number of cards in each of the following suits: CLUBS, DIAMONDS & SPADES.
How many hearts were initially in the partial deck?
Number of clubs=spades=diamonds=x
Hearts = h
Probability of red on first draw = (x+h)/(3x+h)
Probability of red of second draw given red on first draw = (x+h1)/(3x+h1)
Product = probability both draws red = 1/2
Simplifying gives
0=7x²+ 2xh  x  h² + h
Use the quadratic formula to solve for x.
The discriminant is 32h²32h+1 which is only a perfect square for h=6 or 12.
If h=6, x=1.428 or 3
If h=12, x=3 or 6.286
The only solution that makes sense is 12 hearts, 3 of each other suit.
Checking
(15/21) * (14/20) = 1/2
Edited on March 6, 2014, 11:19 am

Posted by Jer
on 20140305 10:26:11 