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Words count (Posted on 2014-03-25) Difficulty: 4 of 5
(D3)How many subsets of (a,b,c, … x,y,z) contain no letters neighboring each other in the English ABC (26 letters)?

(D4)How many "words" (i.e, ordered subsets from (a,b,c, … x,y,z)) contain no neighboring letters that neighbor each other in the English ABC (26 letters)?

No Solution Yet Submitted by Ady TZIDON    
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Some Thoughts re: solution to part 1; thoughts on part 2 | Comment 7 of 8 |
(In reply to solution to part 1; thoughts on part 2 by Charlie)

Not sure what significance it has, if any, but the only other "pattern" I see in the higher columns of your table is that n(a,s) is evenly divisible by 2(a-s+1).  Unfortunately I don't see a pattern in the rest of the divisors that would lead to a closed-form solution for n(a,s).  For example, for n(a,5):

n(5,5) = 14 = 2*7

n(6,5) = 124 = 4*31

n(7,5) = 582 = 6*97

n(8,5) = 1928 = 8*241

n(9,5) = 5110 = 10*511 = 10*7*73

n(10,5) = 11604 = 12*967

n(11,5) = 23534 = 14*1681 = 14*41*41

n(12,5) = 43792 = 16*2737 = 16*7*17*23

Edited on March 26, 2014, 9:04 am
  Posted by tomarken on 2014-03-26 09:01:02

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