All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
A Quicky III (Posted on 2014-04-09) Difficulty: 1 of 5
If each of the a,b,c,d is a decimal digit - for how many ordered quadruplets (a,b,c,d) is the sum S= a+b+6c+d divisible by 3 ?

Answer: within 20 sec.

No Solution Yet Submitted by Ady TZIDON    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution How to do it quickly Comment 9 of 9 |
6c is always divisible by 3. Therefore, a+b+d is divisible by 3, and c can be any digit. Let abd be a 3-digit number from 000 to 999. There are 334 numbers from 000 to 999 that are divisible by 3. Therefore, there are 334 numbers for abd. Since c can be any digit, there are 334*10=3340 quadruplets (a, b, c, d).


  Posted by Math Man on 2014-04-12 22:18:40
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information