Some numbers remain numbers when turned upside down (using digits 0125689, with no final 0's):
1, 2, 5, 6, 8, 9, 11, 12, … etc
IF a1=1, a2=2, a3=5,... a8=12,…, etc
b. Evaluate a1000
c. If an= 888, what is n?
(In reply to re: Direct Basic solution......corrections...
by Ady TZIDON)
Well, that's what I get for showing off. I guess I should have used my procedure with Charlie's known answers. Or checked my work. Or both.