I couldn't help noticing that my "exact" answer has many more digits in fractional form than Charlie's "exact" answer. Clearly, at least one of them is inexact.

Upon reflection, it seams that mine is the "inexact" one. The problem, for instance, is that the probability that the first 7 digits contain the author's phone number is not independent of the probability that 2nd through 8th digits do.

The probability that the first one does not contain the number is 1-(1/6)^7 = 279935/279936 = .999996427**75**.

But if it does not contain the number, then it increases very very slightly the probability that digits 2 - 8 do, because it is not possible that digits 2-8 are 543663n. In this case, the probability that digits 2-8 does not contain the number is

(279935-6)/(279936-6) = .999996427**67**

**Charlie: Could I trouble you to calculate my original solution with some precision? I am curious how close it is to the correct answer. **