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 Wedding Wangle (Posted on 2014-07-09)
Horace has decided that he will marry one of the three ladies - Alice, Beatrice and Candice.

[1] Of Alice and Beatrice:
(a) Either both have hazel eyes or both do not.
(b) One is red-haired and the other is not.

[2] Of Alice and Candice:
(a) Either both are red-haired or both are not.
(b) One is slender and the other is not.

[3] Of Beatrice and Candice:
(a) One has hazel eyes and the other does not.
(b) One is slender and the other is not.

[4] Of the mentioned characteristics - hazel eyes, red-haired, and slender:
(a) If any of Alice, Beatrice, and Candice has exactly two of these characteristics, then Horace will marry only the lady with the least number of them.
(b) If any of Alice, Beatrice, and Candice has exactly one of these characteristics, then Horace will marry only the woman with the greatest number of them.

Which one of the ladies will Horace marry?

 No Solution Yet Submitted by K Sengupta Rating: 1.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re: possible solution | Comment 5 of 6 |

(2,1,1) is not a possible distribution because it leads to a contradiction between 4a and 4b.

There are only two possible distributions that do not lead to a contradiction:

(1) Alice is NOT hazel, red-haired, NOT slender

Beatrice is NOT hazel, NOT red-haired, NOT slender

Candice is hazel, red-haired, slender.

By 4b, Horace will marry Candice.

(2) Alice is hazel, NOT red-haired, slender

Beatrice is hazel, red-haired, slender

Candice is NOT hazel, NOT red-haired, NOT slender

By 4a, Horace will marry Candice.

Since both of these possibilities lead to Horace marrying Candice, that must be the intended solution.

 Posted by tomarken on 2014-07-10 09:29:24

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