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Unknown Power Ponder (
Posted on 20140811
)
Each of x, y and z are positive integers such that x+y+z=2006 and, x!*y!*z! = p*10
^{q}
, where each of p and q is a positive integer and p is not divisible by 10.
What is the smallest value of q?
No Solution Yet
Submitted by
K Sengupta
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re: Paper and pencil solution (spoiler?)
 Comment 2 of 4 
(In reply to
Paper and pencil solution (spoiler?)
by Steve Herman)
152*2+188=492
Posted by
Ady TZIDON
on 20140812 02:21:07
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