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Unknown Power Ponder (Posted on 2014-08-11) Difficulty: 3 of 5
Each of x, y and z are positive integers such that x+y+z=2006 and, x!*y!*z! = p*10q, where each of p and q is a positive integer and p is not divisible by 10.

What is the smallest value of q?

No Solution Yet Submitted by K Sengupta    
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Hints/Tips re(3): Paper and pencil solution (spoiler?) Comment 4 of 4 |
(In reply to re(2): Paper and pencil solution (spoiler?) by broll)

There are many other solutions (all getting 492), inter alia


124 +1124 +758,123 +1124+759, 624+623+759  ,

1249 + 374 +383 ,1248+374+384   etc  etc


I will adddres this puzzle later                  


 

 


  Posted by Ady TZIDON on 2014-08-12 09:49:12
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