Each of x, y and z are positive integers such that x+y+z=2006 and, x!*y!*z! = p*10^q, where each of p and q is a positive integer and p is not divisible by 10.

What is the smallest value of q?

(In reply to re(2): Paper and pencil solution (spoiler?) by broll)

There are many other solutions (all getting 492), inter alia

124 +1124 +758,123 +1124+759, 624+623+759  ,

1249 + 374 +383 ,1248+374+384   etc  etc

I will adddres this puzzle later                  

 

 

Posted by Ady TZIDON on 2014-08-12 09:49:12