Each of x, y and z are positive integers such that x+y+z=2006 and, x!*y!*z! = p*10q, where each of p and q is a positive integer and p is not divisible by 10.
What is the smallest value of q?
(In reply to re(2): Paper and pencil solution (spoiler?)
There are many other solutions (all getting 492), inter alia
+758,123 +1124+759, 624+623+759 ,
1249 + 374
+383 ,1248+374+384 etc etc
I will adddres this puzzle later