perplexus.info :: Liars and Knights : Liars Logic 2

Liars Logic 2 (Posted on 2014-03-17)

You're once again on the island of Knights, Knaves, and Liars. You meet 6 natives who are all different ages between 20 and 50. They make the following statements to you:

Andy says:

Brad is a Liar.
Fred is a Liar.
I'm one year older than Brad.
I'm three years older than Chet.
The sum of our ages is divisible by 3.

Brad says:

Chet is a Liar.
Andy is a Liar.
I'm one year older than Chet.
I'm three years older than Doug.
My age is divisible by 5.

Chet says:

Doug is a Liar.
Brad is a Liar.
I'm one year older than Doug.
I'm three years older than Eddy.
My age is divisible by 2.

Doug says:

Eddy is a Liar.
Chet is a Liar.
I'm one year older than Eddy.
I'm three years older than Fred.
I'm the oldest.

Eddy says:

Fred is a Liar.
Doug is a Liar.
I'm one year older than Fred.
I'm three years older than Andy.
The sum of our ages is divisible by 11.

Fred says:

Andy is a Liar.
Eddy is a Liar.
I'm one year older than Andy.
I'm three years older than Brad.
The sum of our ages is a perfect square.

Figure out the ages of the six natives.

See The Solution Submitted by tomarken

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Comments: ( Back to comment list | You must be logged in to post comments.)

Are these puzzles interesting?

Comment 2 of 2 |

Correct as usual, Charlie.

Not to diminish the computer solutions, because I'm seriously impressed by Charlie's ability to translate a problem like this into code that produces a solution, but I'm still hoping someone will post an analytical solution to this and/or the previous "Liars Logic" puzzle before I post my own solutions.

Are they too confusing? Just not very interesting? I had fun creating these and was planning to do some more in a similar vein, but I want to make sure I'm properly interpreting the lack of responses before I make some new ones. I realize it's pretty slow around here these days but I figured the regulars here would work these out pretty quickly. :)

Posted by tomarken on 2014-03-17 20:04:33

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