(In reply to re: Any thoughts on this one?
by Ady TZIDON)
I guess I'd prefer just a small hint. I'd like to be able to solve it myself but I can't seem to get past the condition that no coin may be weighed more than twice.
As you mention, this is a familiar problem and the traditional solution might require weighing a coin more than twice. I don't see how adding that additional restriction produces a different solution. This puzzle is not in "Tricks" so I assume there's a legitimate solution but I'm having a hard time seeing what it could be.
Posted by tomarken
on 2014-07-02 09:46:41