answer :

** 10**

**C**onsider the number 20102010...2010729, where 2010 is repeated n times.

The sum of digits on odd- counting from left- places is 3n+16

Ob even the sum is 2

**COMPARING MODULO 11:**

**3n+16=3n+5=2 mod11**

**3n=8 mod 11**

**3*10=30 22+8**

**Since 10 is less than 11 , it is a minimal soluition**

**-**

**21,32,43 etc would work as well**