(In reply to
re(2): solution by Charlie)
As Jer has pointed out, the treating of a given vowel as if it were a consonant will include not only disorderings of that consonant, but also, by happenstance, all the intended orderings (i.e., reversed) as well. Also, among the disorderings, interchange of two adjacent vowels' positions will be counted twice: once with each of the two vowels in question.
By the first of these two factors that were overlooked, instead of adding in the ordered case (16331695263739215360000 ways), we should have subtracted it out 4 times (equivalently subtracting it out once for each of the 5 vowel conditions, then adding it in for itself).
The second of these two types of previously overlooked condition involves the double counting of four specific orderings. As they are specific orderings, they also each have the same number of ways: 16331695263739215360000.
Bottom line, it seems we should take the sum of the five leftoutvowel conditions and subtract eight times the specificorder count:
9145749347693960601600000 + 1959803431648705843200000 + 186834593817176623718400000 + 1959803431648705843200000 + 1959803431648705843200000  8 * 16331695263739215360000
= 201729099897706788126720000

Posted by Charlie
on 20140925 09:42:30 