Consider an arbitrary hyperbola without a marked center or foci.
Using only a straightedge and compass construct the transverse and conjugate axes.
(In reply to re(2): Solution
After constructing the axes…
Use points P(2a, 0) on the x axis and Q(2a, sqrt(3)b) on the
curve, to construct a 30o, 60o, 90o triangle
PQR so that
PQ = sqrt(3)b, QR = b, PR = 2b.
Then use the length 2b to construct the point S(2a, 2b) so that
OS is an asymptote.
Posted by Harry
on 2014-10-09 12:08:53