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Hyperbola Axes Hinder (Posted on 2014-10-03) Difficulty: 3 of 5
Consider an arbitrary hyperbola without a marked center or foci.
Using only a straightedge and compass construct the transverse and conjugate axes.

No Solution Yet Submitted by K Sengupta    
Rating: 4.0000 (1 votes)

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Some Thoughts re(3): Solution. On 2nd thoughts | Comment 6 of 7 |
(In reply to re(2): Solution by Harry)

A more direct method

After constructing the axes…

Use points P(2a, 0) on the x axis and Q(2a, sqrt(3)b) on the

curve, to construct a 30o, 60o, 90o triangle PQR so that

PQ = sqrt(3)b, QR = b, PR = 2b.

Then use the length 2b to construct the point S(2a, 2b) so that

OS is an asymptote.




  Posted by Harry on 2014-10-09 12:08:53

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