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A periodical fraction (Posted on 2014-07-11) Difficulty: 3 of 5

Find the only existing solution.

See The Solution Submitted by Ady TZIDON    
Rating: 1.5000 (2 votes)

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re: Solution Comment 3 of 3 |
(In reply to Solution by broll)

Nice start, Broll, and thanks for citing my method.

However, there is no reason to assume that GO/IN is a fraction that has been reduced to lowest terms.

kx = 999 = 27*37, so IN could be 27 or 37.  But IN could also be a multiple of 27 (ie, 54 or 81) or a multiple of 37 (ie, 74).  

This turns out not to be the case, but a full analytical solution needs to deal with that possibility.

  Posted by Steve Herman on 2014-07-12 09:47:18
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