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Three Line Segment Sum (Posted on 2014-05-31) Difficulty: 4 of 5

Let A, B, and C be circles with equal radii and tangent externally
pairwise. Let O be the circle tangent externally to A, B, and C and
P any point on O. For X∈{A,B,C}, let X' be one of the two points
on X such that line PX' is tangent to X and let x = |PX'|.

Prove that (a+b-c)(b+c-a)(c+a-b) = 0.

See The Solution Submitted by Bractals    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Trig approach Comment 2 of 2 |
(In reply to Trig approach by Harry)

Sorry Harry. My approach is similar to yours.

I would also like to see a geometric proof. 

  Posted by Bractals on 2014-06-07 23:55:07
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