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The decisive straw (Posted on 2014-07-25) Difficulty: 3 of 5
One by one straws are placed on a mathematical camelís back.
The straws have random weight, being drawn independently from the uniform distribution 0 to 1.
The camelís back breaks when the total weight of the straws exceeds 1.

Whatís the expected weight of the straw that breaks the camelís back?

Source: abridged from "Mind your decisions" blog.

No Solution Yet Submitted by Ady TZIDON    
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Comments: ( Back to comment list | You must be logged in to post comments.)
a bit more Comment 6 of 6 |
Here are some more expected values:
the ultimate straw is              (2-e/2)  ~ 0.6409
the penultimate total weight is (e-2)    ~ 0.71828
the ultimate total weight is      (e/2)    ~ 1.3591

  Posted by Larry on 2014-07-30 17:48:45
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