A tall tower is constructed on the side of a hill with uniform incline. Two guy wires are attached to the top of the tower and to points on the ground 50.0 feet from the tower  one directly upslope and one directly downslope. If the wires are 284.7 feet and 303.5 feet respectively, what is the angle of incline of the hill and how high is the tower?
(In reply to
Solution  Spoiler by Kenny M)
If we let d = 303.5, u = 284.7, and s = 50; then your equations
become
d^2 = h^2 + s^2 + 2*h*s*sin(A)
and
u^2 = h^2 + s^2  2*h*s*sin(A)
Using these two equations
we can solve for h and A with d, u, and s given
or
we can solve for d and u with h, A, and s given.
Note: The second option is what I think Jer did to get d and u.
Edited on June 19, 2014, 12:04 am

Posted by Bractals
on 20140618 23:01:50 