A tall tower is constructed on the side of a hill with uniform incline. Two guy wires are attached to the top of the tower and to points on the ground 50.0 feet from the tower - one directly up-slope and one directly down-slope. If the wires are 284.7 feet and 303.5 feet respectively, what is the angle of incline of the hill and how high is the tower?
(In reply to Solution - Spoiler
by Kenny M)
If we let d = 303.5, u = 284.7, and s = 50; then your equations
d^2 = h^2 + s^2 + 2*h*s*sin(A)
u^2 = h^2 + s^2 - 2*h*s*sin(A)
Using these two equations
we can solve for h and A with d, u, and s given
we can solve for d and u with h, A, and s given.
Note: The second option is what I think Jer did to get d and u.
Edited on June 19, 2014, 12:04 am
Posted by Bractals
on 2014-06-18 23:01:50