We can simplify things talking 4 away from each of x, y and z, since this will remove 94 4's.
H = 0x + 6y + 15z + 4*94
(H376) = 6y + 15z
(H376)/3 = 2y + 5z
Call G = (H376)/3 and we can rephrase the conditions and question as the equivalent:
(i) y+z ≤94, and:
(ii) G = 2y + 5z
How many distinct values of G is (sic) possible?
Edited on October 17, 2014, 6:45 am

Posted by Jer
on 20141016 10:16:51 