Consider a right angled triangle ABC situated in the XY plane, where AB is the hypotenuse.
Given that:
(i) AB = 60, and:
(ii) The medians through A and B lie along the lines y=x+3 and y=2x+4 respectively.
Determine the area of triangle ABC.
I'm pretty sure this is the only solution.
Area of triangle ≈9.40445
A=(16.20718,13.20718)
B=(16.35558,37.07117)
C=(3.32841,17.86339)
Trying to solve analytically eventually led to a quartic polynomial with terms in the millions. One of them did turn out to be correct, I think.
Edit: The area above does not take my scale into account.
A distance on 1 on my graph was only .15333 cm.
9.40445/1.5333² = 400.018
Edited on December 10, 2014, 10:48 am

Posted by Jer
on 20141208 06:51:09 