All about
flooble

fun stuff

Get a free chatterbox

Free JavaScript

Avatars
perplexus
dot
info
Home
>
Just Math
Equation Exercise (
Posted on 20141216
)
a,b,c,d and e satisfy this system of equations:
2a+b+c+d+e = 6
a+2b+c+d+e = 12
a+b+2c+d+e = 24
a+b+c+2d+e = 48
a+b+c+d+2e = 96
Find 3d+2e without solving the above system.
No Solution Yet
Submitted by
K Sengupta
No Rating
Comments: (
Back to comment list
 You must be logged in to post comments.
)
solving as little as possible
 Comment 2 of 3 
Summing the 5 equations gives
6(a+b+c+d+e)=186
multiplying by 5/6 gives
5a+5b+5c+5d+5e=155 (1)
Add three times the fourth to twice the fifth gives
5a+5b+5c+8d+7e=336 (2)
Subtracting (1) from (2) gives
3d+2e=336155=
181
Posted by
Jer
on 20141216 13:48:49
Please log in:
Login:
Password:
Remember me:
Sign up!

Forgot password
Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ

About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
blackjack
flooble's webmaster puzzle
Copyright © 2002  2019 by
Animus Pactum Consulting
. All rights reserved.
Privacy Information