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Equation Exercise (
Posted on 20141216
)
a,b,c,d and e satisfy this system of equations:
2a+b+c+d+e = 6
a+2b+c+d+e = 12
a+b+2c+d+e = 24
a+b+c+2d+e = 48
a+b+c+d+2e = 96
Find 3d+2e without solving the above system.
No Solution Yet
Submitted by
K Sengupta
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solving as little as possible
 Comment 2 of 3 
Summing the 5 equations gives
6(a+b+c+d+e)=186
multiplying by 5/6 gives
5a+5b+5c+5d+5e=155 (1)
Add three times the fourth to twice the fifth gives
5a+5b+5c+8d+7e=336 (2)
Subtracting (1) from (2) gives
3d+2e=336155=
181
Posted by
Jer
on 20141216 13:48:49
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