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Origamic Revisited (Posted on 2014-12-19) Difficulty: 3 of 5
Consider a paper parallelogram ABCD with AB parallel to CD, AC parallel to BD and ∠ABC = 54o. It is known that |AB| > |AC|.

Vertex B is folded on to vertex D forming the crease EF with E in AB and F in CD such that |EF|= |CD|

Determine the ratio |AB|:|AC|

No Solution Yet Submitted by K Sengupta    
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Some Thoughts playing with GSP Comment 1 of 1
Constructing this in Geometers' Sketchpad, it seems that AB doesn't exceed AC unless E is on an extension of AB beyond the edge of the paper, rather than on segment AB itself.
  Posted by Charlie on 2014-12-19 10:49:33
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