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Omega to Alpha Observation (Posted on 2014-12-23) Difficulty: 3 of 5
Find the smallest value of hexadecimal positive integer N which becomes 4*N when the last digit of N is moved to be the first. For example, turning (2345)16 into (5234)16. How about 2*N? 7*N? 8*N?

No Solution Yet Submitted by K Sengupta    
Rating: 3.0000 (1 votes)

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Solution computer solutions | Comment 1 of 5
 mult(1) = 4
 mult(2) = 2
 mult(3) = 7
 mult(4) = 8
 
 For wh = 1 To 4
 For v = 16 To 1000000
   b16$ = base$(v, 16)
   alp$ = Right(b16$, 1) + Left(b16$, Len(b16$) - 1)
   v2 = fromBase(alp$, 16)
   If v2 = mult(wh) * v Then
     Text1.Text = Text1.Text & v & " " & b16$ & " " & alp$ & " " & v2 & crlf
     DoEvents
   End If
 Next v
 Text1.Text = Text1.Text & crlf & crlf
 Next

finds values only for 4*N and 2*N

original        4*
dec hex      hex  dec
260 104      410 1040    smallest

325 145      514 1300
390 186      618 1560
520 208      820 2080
585 249      924 2340

original          2*
dec hex        hex  dec
67650 10842    21084 135300   smallest

135300 21084   42108 270600
270600 42108   84210 541200


  Posted by Charlie on 2014-12-23 15:09:46
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