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Omega to Alpha Observation (Posted on 2014-12-23) Difficulty: 3 of 5
Find the smallest value of hexadecimal positive integer N which becomes 4*N when the last digit of N is moved to be the first. For example, turning (2345)16 into (5234)16. How about 2*N? 7*N? 8*N?

No Solution Yet Submitted by K Sengupta    
Rating: 3.0000 (1 votes)

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re: computer solutions | Comment 2 of 5 |
(In reply to computer solutions by Charlie)

Seeing you already posted, I thought you may have the answers to 7*N and 8*N.  I do not know what the solution for 7*N is, but I see why you did not find the solution for 8*N, as your upper limit for V is 1000000, when the solution is higher.


2*1084216 = 2480116 = 49505

4*10416 = 40116 = 260

7*  ???

8*102040816 = 810204016 = 135274560


Edited on December 23, 2014, 4:36 pm
  Posted by Dej Mar on 2014-12-23 16:30:39

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