All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Hexadecimal Digit Travail (Posted on 2014-12-25)
Determine the probability that a for a seven-digit positive hexadecimal integer N, the sum of the first four digits of N is equal to the product of the last three digits of N.

 No Solution Yet Submitted by K Sengupta No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
 re(3): computer solution | Comment 4 of 5 |
(In reply to re(2): computer solution by Charlie)

I decided to code the basic program to reduce the semi-manual calculations I had done. Either I had made a small error while using Excel, or, as you had supposed, the number of significant digits may have been the problem. Nonetheless, the program "spit out" the same answer (basically) you had computed:
0.20524025e-2

The program only took about a second to run.

dim s(60)
dim p(60)
for a = 0 to 15
for b = 0 to 15
for c = 0 to 15
p = a * b * c
if p > 0 and p < 61 then
p(p) = p(p) + 1
end if
for d = 1 to 15
s = a+b+c+d
s(s) = s(s) + 1
next d
next c
next b
next a
prob = 0
for i = 1 to 60
prob = prob + (s(i)/4096)*(p(i)/61440)
next i
print str\$(prob)

 Posted by Dej Mar on 2014-12-25 19:16:17

 Search: Search body:
Forums (0)