Show that :

tan(pi/13)*tan(2pi/13)*tan (3pi/13)*tan(4pi/13)*tan(5pi/13)*tan (6pi/13) = 13^1/2.

(In reply to re: Interesting observation by Ady TZIDON)

Right, Ady.
In my first post I was just thinking about the "13" and I used Upper Case N.

In my second post, I was thinking about "n" as the number of terms, so I used lower case 'n'.
N = 2n+1 by that terminology.  Sorry for the confusion

Posted by Larry on 2014-08-18 17:14:29