(In reply to
The sequence, if my trig is right by Charlie)
I got the same recurrence relation that you did.
r_k1^2 = 1  1/(4*r_k^2)
But, it seems in a different way.
It took me a little while to get a closed form
for r_k = f(n,k) such that f(n,n) = 1.
r_1 = f(n,1).
Your value for r at n40 agrees.

Posted by Bractals
on 20140915 09:57:27 