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Angle Ascertainment (Posted on 2015-01-03) Difficulty: 3 of 5
z is a complex number and P is the product of the roots of the equation:
z6 + z4 + z3 + z2 + z2 +1 = 0 with each root having a positive imaginary part.

Given that, P = r(cos θ + i*sin θ), where r > 0 and 0 ≤ θ < 360o

Find θ.

No Solution Yet Submitted by K Sengupta    
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Question the roots of the imaginary | Comment 1 of 2
Half the roots of the sextic z6 + z4 + z3 + 2z2 +1 = 0 will have negative imaginary parts:
x1 ~= 0.129538259 + 0.698949645i
x2 ~= 0.693609354 + 1.074550916i
x3 ~= -0.823147613 + 0.729558742i
x4 ~= 0.129538259 – 0.698949645i
x5 ~= 0.693609354 – 1.084550916i
x6 ~= -0.823147613 – 0.729558742i
Is P to be the product of only the roots where the imaginary parts are positive?
  Posted by Dej Mar on 2015-01-03 22:31:57
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