Find a couple of complex numbers, such that one number is the square of the other and vice versa.
Rem: There will be more than one solution.
z_1 = z_2^2
z_2 = z_1^2
z_1 = (z_1^2)^2
z_1(z_1^3  1) = 0
z_1 = 0, 1, 1/2 + sqrt(3)/2 i, 1/2  sqrt(3)/2 i
Plug into second equation to get corresponding z_2.
Edited on November 19, 2014, 10:03 pm

Posted by Bractals
on 20141119 21:54:44 