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 The medians of medians (Posted on 2014-12-20)
<begin> For a triangle with integer sides a,b,c (none over 2000) evaluate the triplet of its medians ma , mb , mc .
Let those three become sides of a new triangle i.e. (a,b,c) =(ma , mb , mc ).
<end>

It is up to you to find a triplet (a,b,c) such that the above procedure can be executed a maximal number of times, creating sets of “medians“ with integer values only.

The answer should include: (a,b,c) and all interim sets of medians.

Rem: Can be solved analytically.

 Submitted by Ady TZIDON Rating: 4.0000 (1 votes) Solution: (Hide) Sides ......................... .. Medians (1360, 1088, 1392) ....... (1016, 1048, 1264) (1016, 1048, 1264) ......... (1020, 816, 1044) (1020, 816, 1044) ........... (786, 948, 762) (786, 948,762) .............. (783, 765, 612)

 Subject Author Date Possible Solution Harry 2014-12-23 14:54:00 re(2): Solution Dej Mar 2014-12-20 18:47:24 re: Solution Harry 2014-12-20 18:24:16 re: extra challenge: Dej Mar 2014-12-20 16:35:20 extra challenge Ady TZIDON 2014-12-20 13:13:53 Solution Dej Mar 2014-12-20 10:46:01

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