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Enclosed area (Posted on 2002-06-03) Difficulty: 3 of 5
What is the maximum area that could be enclosed by a piece of string 132 cm long? What shape would that area take?

What is the minimum area that could be enclosed by the same string? What shape will it take?

See The Solution Submitted by Dulanjana    
Rating: 2.9091 (11 votes)

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No Subject | Comment 10 of 13 |
well...start with a triangle of perimeter 132 cm...you can increase the area contained in the triangle by making a square with perimeter 132 cm...keep adding sides and you are tending to a cirlce with circumference 132 cm...so i guess that would be the answer... and if 132 = 2pi*r then 66 = pi*r and 66/ pi = r then A= pir^2 so A=pi(66/pi)^2 = 66^2/pi = 4356/pi cm^2
  Posted by daniel carr on 2002-10-28 15:34:30
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