All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Positive Pair Poser (Posted on 2015-05-09) Difficulty: 3 of 5
Determine all possible pairs (x,y) of positive integers with gcd(4x+1, 4y-1) = 1 such that x+y divides 16xy+1

No Solution Yet Submitted by K Sengupta    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Two unhelpful(?) observations | Comment 1 of 8
Observation:

16xy+1 = 16xy + 16y^2 - 16y^2 + 1
       = 16y(x+y) + (4y+1)(4y-1)
       
So, if x+y divides 16xy+1, it also divides (4y+1)(4y-1)
Similarly, it also divides it also divides (4x+1)(4x-1)

Not clear yet how that helps

/******************************/

Different observation.
16xy+1 is odd, so x+y must be odd.

so either x is even and y is odd, or x is odd and y is even

  Posted by Steve Herman on 2015-05-09 14:03:08
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (16)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information