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Number and Factorial Product Puzzle (Posted on 20150602) 

Find all digit three digit positive integers abc such that:
2(abc) = 3*a!*b!*c!
Note: abc is the concatenation of the digits and not the product, so that a is the hundreds digit, b is the tens digit and c is the units digit.
No Solution Yet

Submitted by K Sengupta

Rating: 2.0000 (1 votes)


answer:only

Comment 1 of 1

answer:432 4!*3!*2!=288 2*432=3*288=864


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