Find all digit three digit positive integers abc such that:
2(abc) = 3*a!*b!*c!

Note: abc is the concatenation of the digits and not the product, so that a is the hundreds digit, b is the tens digit and c is the units digit.

answer:432

4!*3!*2!=288

2*432=3*288=864

Posted by Ady TZIDON on 2015-06-02 08:23:31