All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes
Find Points, Maximise Ratio (Posted on 2015-06-05) Difficulty: 3 of 5
Given a plane X, a point M in the plane and a point N not in the plane.

Find all points R in X such that the ratio (NM + MR)/NR is the maximum.

No Solution Yet Submitted by K Sengupta    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
solution | Comment 1 of 6
Let a be then angle MRN
b the angle MNR
and c the angle NMR
then from law of sines we have

sin(a)/MN=sin(b)/MR=sin(c)/NR
then (MN+MR)/NR = (MN/NR)+(MR/NR)
= [sin(a)+sin(b)]/sin(c)
this is maximized when a=b thus we need
MR=NR


Now rotate the plane in question so it coincides with the xy plane.  And flip if needed so M is above the plane.

Now let the points be at the following coordinates:
N (a,b,0)
M (p,q,r)
R (x,y,0)
then we need
MR=NR
MR^2=NR^2
(x-p)^2+(y-q)^2+r^2=(p-a)^2+(q-b)^2+r^2
(x-p)^2+(y-q)^2=(p-a)^2+(q-b)^2

this is the same as saying that R needs to be equidistant from N as a point at (p,q,0)
(p,q,0) is simply the point M projected onto the chosen plane.

Thus the locus of R is simply a circle on the plane with center at N and radius equal to the distance from N to the projection of M onto the plane.

  Posted by Daniel on 2015-06-05 13:02:15
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (1)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information